Question

Two parallel wires are separated by 0.36 m. Wire A carries 4.8 A and Wire B carries 8.9 A, both currents in the same direction. The force on 0.53 m of Wire A is:

Answer 1

The force on 0.53 m of Wire A is 1.3×10^(-5) N.

To find the answer, we need to know about the force on a current carrying wire due to another parallel wire.

What's the force experienced by a current carrying wire of length L due to another current carrying parallel wire?

• The magnetic force experienced by the wire here= μ₀IAIBL/(2πr)
• IA= current in wire A, IB= current in wire B, L = length of wire and r= separation between them

What's the force on 0.53 m of Wire A, if IA, IB, L and r are 4.8A, 8.9A, 0.53m and 0.36 m respectively?

Force = (4π×10^(-7)×4.8×8.9×0.53)/(2π×0.36)

          = 1.3×10^(-5) N

Thus, we can conclude that the force on 0.53 m of Wire A is 1.3×10^(-5) N.

Learn more about the magnetic force here:

brainly.com/question/25932320

#SPJ4