8/25 is the probability that more than 8 of them are strikes.
Lets simplify the problem,
We are given that a softball pitcher has a 0.507 probability of throwing a strike for each pitch. Also, the softball pitcher throws 15 pitches.
The above situation can be represented through Binomial distribution;
P(X = r) = 0,1,2,3,,.....
where, n = number of trials (samples) taken = 15 pitches
r = number of success = more than 8
p = probability of success which in our question is probability of
Throwing a strike for each pitch = 0.507
LET X = Number of strikes
So, it means X ~ n = 15, p = 0.507
So, Probability that more than 8 of them are strikes = P(X > 8)
P(X > 8) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)
After putting the values in it we get,
P = 0.323
P= 8/25 approx
8/25 is the probability that more than 8 of them are strikes.
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