A softball pitcher has a 0.507 probability of throwing a strike for each pitch. If the softball pitcher throws 15 pitches, what is the probability that more than 8 of them are strikes

Respuesta :

8/25 is the probability that more than 8 of them are strikes.

Lets simplify the problem,

We are given that a softball pitcher has a 0.507 probability of throwing a strike for each pitch. Also, the softball pitcher throws 15 pitches.

The above situation can be represented through Binomial distribution;

P(X = r) = 0,1,2,3,,.....

where, n = number of trials (samples) taken = 15 pitches

           r = number of success = more than 8

          p = probability of success which in our question is probability of    

                Throwing a strike for each pitch = 0.507

LET X = Number of strikes

So, it means X ~ n = 15, p = 0.507

So, Probability that more than 8 of them are strikes = P(X > 8)

P(X > 8) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

After putting the values in it we get,

P = 0.323

P= 8/25 approx

8/25 is the probability that more than 8 of them are strikes.

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