A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, how fast was the car initially traveling? assume that any other unbalanced forces are negligible.

Answer: A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, then the car initially traveling with a velocity of 40.28m/s.

Explanation: To find the answer, we need to know more about the Perfectly inelastic collision.

What is perfectly inelastic collision?

Collision is an interaction between two bodies due to which the individual momenta of the colliding bodies are changed, but the total momentum remains constant.
If the colliding bodies stick together after collision, then it is called perfectly inelastic collision.
here, the coefficient of restitution will be equal to 0.
For, inelastic collision, the momentum is conserved, but the energy is not conserved.

How to solve the problem?

let's write the conservation equation of momentum as,

[tex]m_1v_1+0=(m_1+m_2)v_2\\[/tex]

We have to find the value of initial velocity v1,

[tex]mv_1=(m+m)28 sin46\\v_1=2*28*0.719=40.28 m/s[/tex]

Thus, we can conclude that, the initial velocity of the car will be 40.28m/s.

Learn more about the perfectly inelastic collision here:

https://brainly.com/question/28045028

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