Answer:
Step-by-step explanation:
The measure of an angle formed by a Secant and a tangent drawn from the outside point of a circle is half the difference of the intercepted arcs.
[tex]\sf \angle E =\dfrac{arc \ CF - arc \ DF}{2}[/tex]
[tex]\sf53 =\dfrac{arc \ CF-41}{2}[/tex]
53*2 = arc CF - 41
106 = arc CF - 41
106 + 41 = arc CF
[tex]\sf \boxed{\bf \ arc \ CF = 147^\circ}[/tex]
9) If two secants inside a circle, then the angle formed is equal to the half of the sum of intercepted arcs.
[tex]\sf 5x - 7 = \dfrac{27+119}{2}\\\\ 5x - 7 = \dfrac{146}{2}[/tex]
5x - 7 = 73
5x = 73 + 7
5x = 80
x = 80/5
[tex]\sf \boxed{\bf \ x = 16^\circ }[/tex]
