Question

ales volume last weekend for four samples, each consisting of five car dealerships, were as follows: Data Point 1 2 3 4 5 Sample 1 37 15 43 25 21 Sample 2 38 31 12 19 28 Sample 3 16 21 45 32 25 Sample 4 19 10 45 37 22 What is the standard deviation of the distribution of sample means

Answer 1

The sample standard deviation of sample 1 is 11.54,  of sample 2 is 10.21,  of sample 3 is 11.25,  of sample 4 is 14.15.

Given

Data point      sample 1     sample 2           sample 3                sample 4

1                          37                38                       16                             19          

2                          15                31                        21                             10

3                          43                12                       45                             45

4                          25                19                        32                            37

5                          21                 28                       25                             22

We have to find the sample standard deviation of each sample.

We have to first mean of each sample.

Sample mean of 1=141/5=28.2

Sample mean of 2=128/5=25.6

Sample mean of 3=139/5=27.8

Sample mean of 4=133/5=26.6

Sample standard deviation=$\sqrt{}$∑$(x-x bar)^{2}/n-1$

∑$(x-x bar)^{2}$ is calculated in the figure.

Sample standard deviation of sample 1=$\sqrt{532.8/4}$

=$\sqrt{133.2}$

=11.54

Sample standard deviation of sample 2=$\sqrt{417.2/4}$

=$\sqrt{104.3}$

=10.21

Sample standard deviation of sample 3=$\sqrt{506.8/4}$

=$\sqrt{126.7}$

=11.25

Sample standard deviation of sample 4=$\sqrt{801.2/4}$

=$\sqrt{200.3}$

=14.15.

Hence the sample standard deviation of sample 1 is 11.54, sample standard deviation of sample 2 is 10.21, sample standard deviation of sample 3 is 11.25, sample standard deviation of sample 4 is 14.15.

Learn more about standard deviation at https://brainly.com/question/475676

#SPJ4