Answer:
h > 5
h < 0
Step-by-step explanation:
We suppose that a "Special Solution" inequality is one that is technically incorrect, but is written using a compact "shorthand" form.
As written, the inequality claims that 17 < 2, which is false. There can be no value of the variable that will make this true. We presume the intended meaning is ...
17 < 3h +2 or 3h +2 < 2
Special solution
Subtracting 2 from the inequality gives ...
15 < 3h < 0
Dividing by 3 gives ...
5 < h < 0
There is no value of h that is both greater than 5 and less than 0, so we presume this means the OR (union) of the solution sets ...
h > 5
h < 0
