Question

Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon. Calculate the expected yield of lead if 50.0 kg of lead oxide is heated with 50.0 kg of carbon.

Answer 1

Find the expected yield of lead:

The expected yield of lead if 50.0 kg of lead oxide is heated with 50.0 kg of carbon is 46 kg

Calculation:

First and foremost, we must correctly write the equation of reaction in order to answer this issue. This is what it is:

PbO(s) + C(s) → Pb(l) + CO (g)

We continue from here. The limiting reactant should be found, however finding out how many moles of each reactant are present is the only way to do so.

The number of moles is calculated using the formula: the mass of each reactant divided by the molar mass of each reactant.

Mass of PbO is 50kg = 50000g

Molar mass of PBO = 223.20g/mol

The number of moles is thus 50000/223.2 = 224 moles

For carbon, mass is also 50kg = 50000g

Molar mass is 12g/mol

Number of moles of carbon = 50000/12 = 4166.6 moles

We can observe from the number of moles that there are more moles of carbon than PbO. This indicates that the limiting reagent is PbO.

So, in order to determine percentage yield, we employ it.

Since we have a mole ratio of 1 to 1, the number of moles of lead created is equal to the number of moles of lead oxide, which is 224.

The molar mass of lead = 207.20 g/mol

The mass of lead formed = moles of lead x molar mass of lead

The mass of lead formed = 207.20 x 224 =  46,412.8 g = 46 kg

Hence, the expected yield is 46 kg.

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