Question

Question
If the length of the side of a square is 3x - y, what is the area of the square in terms of x and y?
3x² - 2xy + y²
3x² - 6xy + y²
09x² +6xy-y²
9x² - 6xy + y²

Answer 1

The area of the square is given by the  quadratic expression:

$A = 9x^2 - 6xy + y^2$

How to express the area of the given square?

If we have a square whose side measures S, the area of said square is given by the equation:

$A = S^2$

In this case, we know that the side length of our square is given by:

$S = 3x - y$

Replacing that in the area equation we get:

$A = (3x - y)^2$

Now we just need to expand that product, we will get:

$A = (3x - y)^2 = (3x)*(3x) + (3x)*(-y) + (-y)*(3x) + (-y)*(-y) \\\\A = 9x^2 - 6xy + y^2$

Then we can see that the correct option is the last one.

If you want to learn more about squares you can read:

https://brainly.com/question/24487155

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