Respuesta :

she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

According to the statement

Janice bought total items = 30

Price of items are 30 cents, 2 dollars, or 3 dollars.

Total purchase price of Janice = 30$

If we let she bought 10 items at price of 3$, Then it is not possible

So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.

we know that 1 CENT = 0.01 $

We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.

Now, Let she bought 20 items at price of 0.01$

Then 20*0.3 = 6$

It means 30$-6$ = 24$

24$ are left to purchase the things which are at price of 2$ and 3$.

If we let she purchase 4 items at cost $3 then

Then 4*$3 = 12$

It means 24$-12$ = 12$

Now, with remaining money she bought 6 items at cost $2.

So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

Learn more about ELIMINATION METHOD here

https://brainly.com/question/24078509

#SPJ4

ACCESS MORE