Question

You have one type of chocolate that sells for $1.50/lb and another type of chocolate that sells for $6.50/lb. You would like to have mix the $1.50/lb type with 10 lbs of the $6.50/lb type to make a chocolate mixture that sells for $2.50/lb. How much of the $1.50/lb type will you need to obtain the desired mixture

Answer 1

14 of the $1.50/lb type will you need to obtain the desired mixture.

According to the statement

Chocolate A that sells for $1.50/lb

Chocolate B that sells for $6.50/lb

Then in equation form the quantity of mixture will

A + B = X

then

$1.50A + $6.50(10) = X

1.50A + 65 = X -(1)

after solving the equation the value of a and b will become

A = 14.

So, 14 of the $1.50/lb type will you need to obtain the desired mixture.

Learn more about ELIMINATION METHOD here https://brainly.com/question/12691830

#SPJ4