Between 48% and 54% believe that their health is extremely important.
According to the statement
Given that a random sample of 1001 Americans aged 18-24 years showed that 51% believe their health is extremely important.
Here
Sample size n =1001
sample proportion p = 0.51
By these values we calculate the Standard error of proportion.
So, Standard error of proportion = 0.0158.
Since sample size is sufficiently large we can take Z critical value for confidence interval
Z critical value for 95% = 1.96
Margin of error = ±1.96*std error
= ±0.0310
confidence interval = 0.51 ±0.0310
= (0.48, 0.54)
So, Between 48% and 54% believe that their health is extremely important.
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