The equation of a line parallel to the given line and passing through the point (0, 8) is 5y - 3x = 40
The equation of a line in point-slope form is expressed as;
y - y0 = m(x -x0)
where
m is the slope
(x0, y0) is the point on the line
Given the following parameters
Point (0,8)
Slope from the equation = 3/5
Substitute
y - 8 = 3/5(x - 0)
5(y -8) =3x
5y - 40 = 3x
5y - 3x = 40
Hence the equation of a line parallel to the given line and passing through the point (0, 8) is 5y - 3x = 40
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