Students who receive a grade of at least a C must have a minimum score of 50.38.
We may assume that the cut-off will be below 67.66 % because that percentage is more than 50%.
To get the value of 67.66 - 50 = 17.66, we must search in a regular normal table.
Hence, A z value of 0.458 will cause that value to occur.
Next, increase the standard deviation of 9 by 0.458.
The result is 4.122.
This indicates that the threshold for a student earning a C or higher is the mean minus 4.122.
So, the final result is 54.50-4.122 = 50.38.
Learn more about standard deviation here:
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