Suppose that a test for a disease correctly gives positive results for 95% of those having the disease and correctly gives negative results for 90% of those who don't have the disease. Suppose also that the incidence of the disease is 1%. If a person tests positive for the disease, what is the chance that they have the disease

Respuesta :

If the test gives positive results for 95% of those having disease and correctly gives negative results for 90% of those who don't have disease and the incidence of the disease is 1% then the chance of having disease is 0.0105.

Given that a test for a disease correctly gives positive results for 95% of those having the disease and correctly gives negative results for 90% of those who don't have the disease.

We have to calculate the chance of having disease.

Probability that test is correct in determining the disease when person is suffering from it is 0.95.

Probability that test is not correct in determining the disease when person is suffering from it is 1-0.95=0.05.

Probability that test is correct in determining that the person is not suffering from disease  when person is not suffering from it is 0.90.

Probability that test is not correct in determining that the person is not suffering from disease  when person is not suffering from it is 1-0.9=0.10.

The chance of having disease is equal to incidence of disease multiplied by probabilities that the test has corectly determined disease when personis suffering from it and when test is not able to determine the disease when person is suffering from it.

Chance=0.01*0.95+0.01*0.10

=0.0095+0.001

=0.0105.

Hence the chance of having disease is 0.0105.

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