The probability that the call center will get fewer calls than 440 is 0.26115.
Given mean of 4900 and standard deviation of 700.
We have to calculate the probability that the call center will get fewer than 4400 calls.
Probability lies between 0 and 1.
μ=4900
σ=700
We can apply z as well as t statistics because the sample size is not given.
We are applying z statistics.
P(X<4400)=0.5-P(4400<X<4900)
z=X-μ/σ
where μ= mean
σ=standard deviation
z=4400-4900/700
=-500/700
=-0.71
p value of -0.71 is 0.23885.
So the p value of calls less than 4400 is 0.5-0.23885=0.26115.
Hence the probability that the call center will get calls less than 440 is 0.26115.
Learn more about z test at https://brainly.com/question/14453510
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