Question

In a sample of 16 employees randomly selected at a company, the average age is 25 years and the standard deviation is 2 years. We want to test if the average age of all employees is greater than 24. If ages are normally distributed in the population, using a significance level of 0.05, we can claim that the population mean is: Group of answer choices

Answer 1

If ages are normally distributed then using a significance level of 0.05 , we can claim that the population mean is greater than 24.

Given sample mean of 25 years , sample size of 16 ,standard deviation of 2 years.

We have to find whether the population average is greater than 24.

We have to use t test because n is less than 30. It is right tailed.

We have to first form Hypothesis.

$H_{0}$:μ>24,

$H_{1}$:μ<24.

t=X-μ/S/$\sqrt{n}$

t critical at 5% significance level and degree of freedom=15    (16-1)=1.7531

t=24-25/2/$\sqrt{16}$

=-1/0.5

=-2

Because 1.7531 is greater than -2 so we will accept the null hypothesis.

Hence we can say that the average of population is greater than 24.

Learn more about t test at https://brainly.com/question/6589776

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