The density of mobile electrons in copper metal is 8.4 1028 m-3. Suppose that i = 9.0 1018 electrons/s are drifting through a copper wire. (This is a typical value for a simple circuit.) The diameter of the wire is 3.6 mm. In this case, about how many minutes would it take for a single electron in the electron sea to drift from one end to the other end of a wire 35 cm long? minutes

A rate of electric charge flowing past a place or region is called an electric current. A net passage of electric charge through a region creates an electric current.

Here,

ρ is the density of electrons = 8.4×10²⁸ kg/m³

i is the electric current =9.08×10¹⁸ electrons/sec

d is the diameter of the wire =3.6 mm = 0.0036 m

r is radius, r = d/2, r = 1.8 mm = 0.0018 m

l is the length of wire = 34 cm = 0.34 m

v is The volume of the wire

We know that Volume:

V = π r^2* l

V = (3.14* 0.0018^2) 0.34

V = 3.45* 10^-6 m³

Now,

no of electrons= ρ × V

n = 8.4×10²⁸ * 3.45* 10^-6

n = 2.898 * 10^ 23

The time required for the drifting electron is equal to the ratio of the number of electrons to the electric current flows.

T = n/i

T = 2.898 * 10^ 23 / 9.08×10¹⁸

T = 0.3191 * 10^5 s

T = 531 minutes

Hence,

It would take 531 minutes for a single electron in the electron sea to drift from one end to the other end of a wire 35 cm long.

Learn more about electric charge here:

https://brainly.com/question/15180042

#SPJ4