Question

An electron moving through an electric field is observed to have an acceleration of 1.20 1016 m/s2 in the x direction. What is the magnitude and the direction of the electric field that produces this acceleration

Answer 1

The magnitude is 5.69 × 10^4  N/C and the direction is  opposite to the acceleration of electron.

Equation of force on a charge is -

                F = ma

→             qE = ma

The acceleration of an electron is 1.201016 m/s².

→         E =  ma/q

  plug in the values

          E = 9.11 × 10^-31 kg × 1×10^16 m/s² i / -1.6 × 10^-19 C

          E = 5.69 × 10^4  N/C   (-i)

so, magnitude is 5.69 × 10^4  N/C  and field is along negative x-axis

Thus, it has opposite direction to the acceleration of electron.

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