Question

a major textile dye manufacutrer developed a new yellow dye. the dye has a percent composition of 75.95%C, 17.72%n and 6.33%H by mass with a molar mass of about 240g/mol. determine the molecular formula of the dye

Answer 1

The molecular formula of dye:

A major textile dye manufacturer developed a new yellow dye with a molecular formula $C_{15}N_{3}H_{15}$.

Given:

Percentage composition:

C = 75.95%

N = 17.72%

H = 6.33%

Molar mass = 240 g

To find: molecular formula of dye

Calculation:

Let's assume the mass of the compound is 100 gm.

So,  Mass of C = 75.95 gm

Mass of N = 17.72 gm

Mass of H = 6.33 gm

The number of moles = given mass/mass

Therefore, the number of moles of C = 75.95/12 = 6.33

The number of moles of N = 17.72/14 = 1.27

Number of moles of H =6.33/1 = 6.33

Simplest ratio:

C = 6.33/1.27 = 4.98 =5

N = 1.27/1.27 = 1

H = 6.33/1.27 = 4.98 =5

Therefore, the empirical formula is $C_{5}NH_{5}$

The mass of empirical formula = 12 x 5 + 14 + 1 x 5 = 79 gm

Number of moles= molar mass/ empirical formula

n = 240/79 = 3.04 =3

Therefore, molecular formula = empirical formula x n

Hence, molecular formula = $C_{15}N_{3}H_{15}$

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