The probability of two successes in seven trials is 0.0774144.
The probability can be found using the binomial formula.
The probability of success is given as 0.6.
Therefore, the probability of failure is 0.4.
We have to find the probability of two successes in seven trials.
It is given by:
[tex]P = nC_x p^{n} q^{n-x}\\=7C_{2} (0.6)^{2} (0.4)^{7-2} \\=7C_{2} (0.6)^{2} (0.4)^{5} \\=\frac{(7)(6)}{(1)(2)} (0.36)(0.01024)\\=0.0774144[/tex]
The probability of two successes in seven trials is found to be 0.0774144.
Therefore, we have found that the probability of two successes in seven trials is 0.0774144.
Learn more about probability here: https://brainly.com/question/24756209
#SPJ4
