The concentration of the acetic acid:
The concentration of the acetic acid before titration is 0.128M
Reaction of phenolphthalein with NaOH:
The sodium hydroxide will start interacting with phenolphthalein as soon as enough sodium hydroxide has been added to the acetic acid such that there is no longer any unreacted acetic acid. Pink solution is produced when phenolphthalein and sodium hydroxide combine.
Calculation:
The balanced equation:
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
Given:
Quantity of NaOH = 0.1067 M
Volume of NaOH = 30.07 ml
= 30.07 / 1000
= 0.03007 L
For weak acid and strong base titration = Moles of acetic acid = moles of NaOH
Moles of NaOH = concentration X volume
0.1067 X 0.03007 = 0.0032
Thus, moles of acetic acid = 0.0032mole,
By employing the formula,
Concentration = Moles/Volume
= 0.0032/0.025
= 0.128M
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