The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
From the question:
Mars: F(x) = 2/3[tex]\sqrt{64x}[/tex]
Therefore, If x = 15
Then:
f (15) = 2/3 [tex]\sqrt[8]{15}[/tex]
= 16/3[tex]\sqrt{15}[/tex]
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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