Question

A parallel plate capacitor fully charged to voltage V is connected to the battery (the voltage on the plates remains fixed). If the plates are pulled away from each other, how would it affect the charge on the capacitor

Answer 1

Charge will decreases.

A parallel plate capacitor when it is fully charged to voltage V is given as:

                    C = Q/V

The capacitance of parallel plate capacitor with two plates of Area A separated by distance d and no dielectric material between plates is

                    C = ε₀ A /d

since from above equation it shows C is proportional to Q and also C is inversely proportional to distance d.

So, ATQ when d increases C will decrease which in result decreases charge on the capacitor.

Thus,  Charge will decrease.

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