A local pizza parlor has the following list of toppings available for selection. The parlor is running a special to encourage patrons to try new combinations of toppings. They list all possible three-topping pizzas (3 distinct toppings) on individual cards and give away a free pizza every hour to a lucky winner. Find the probability that the first winner randomly selects the card for the pizza topped with ham, artichoke hearts, and pepperoni.

The probability that the first winner randomly selects the card for the pizza topped with ham, artichoke hearts, and pepperoni is 1/560 given that there are 16 toppings to choose from. This can be obtained by finding the total number of all possible three-topping pizzas (3 distinct toppings) using combination formula and finding the probability.

What is the required probability?

Given that there are 16 toppings,

the total number of all possible three-topping pizzas,

ⁿCₓ = [tex]\frac{n!}{x!(n-x)!}[/tex] = 16!/[3!(16-3)!] = 16!/[3!(13)!] = 14×15×16/3×2 =560

Probability of choosing pizza topped with ham, artichoke hearts, and pepperoni,

P(ham, artichoke hearts, pepperoni) = 1/560

Hence the probability that the first winner randomly selects the card for the pizza topped with ham, artichoke hearts, and pepperoni is 1/560 given that there are 16 toppings to choose from.

Learn more about permutations and combinations here:

brainly.com/question/13387529

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