Question

Agents J and K work in a long hallway with 4000 equally-spaced, consecutive offices. The agents decide to walk toward each other so they can meet and have lunch together. Agent J has recently been relocated from office 2013 to office 1. His former office neighbor, Agent K, is still in office 2014. Assuming that Agent J can walk at a rate of 25 offices per minute, and Agent K walks at 36 offices per minute, what office will they meet at if they leave at the same time

Answer 1

At office 826 they will meet if they leave at the same time.

How many offices are there between agents J and K?

It is given that,

Agent J has recently been relocated from office 2013 to office 1. But his former office neighbor, Agent K is still in office 2014.

So, there are  (2014 - 1) - 1 = 2012 offices in between them.

How much time is required for them to walk the whole distance?

It is given that,

Agent J can walk at a rate of 25 offices per minute, and Agent K walks at 36 offices per minute.

So,

Per minute they cross

= 25 + 36

= 61 offices.  

Thus, the time required for crossing all the 2012 offices is,

= 2012/61

= 32.9 ≅ 33 minutes

Then,

They will meet at

1 + 25(33) = 826 office (or)

2014 - 36(33) = 826 office (Negative since opposite direction)

Therefore, both of them meet at office 826.

Refer similar problem here:

https://brainly.com/question/1267118

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