A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 T. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod? A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 T. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod? 7.6 A 2.5 A 9.8 A 4.9 A 1.2 A

Respuesta :

The minimum current in the rod needed is 4.9 A for the magnetic force to cancel the weight of the rod.

What is a magnetic field?

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A moving charge in a magnetic field experiences a force perpendicular to its velocity and the magnetic field.

Force on a current carrying rod due to the magnetic field is given as:

F = i*L*B

Where,

i is current in the rod.

L is the length of rod = 1 m

B is magnetic field = 0.10 T

Here,

The Magnetic force is balanced by the weight of the rod

i*L*B = m*g

i* ( 1 )* ( 0.10 ) = 0.05 * 9.8

i = 4.9 A

Hence, option d is correct.

The minimum current in the rod needed is 4.9 A for the magnetic force to cancel the weight of the rod.

Learn more about the magnetic field here:

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