In the figure, j∥k and m∠2 = 117°. What is the m∠3 ? Enter your answer in the box.
![In the figure jk and m2 117 What is the m3 Enter your answer in the box class=](https://us-static.z-dn.net/files/d74/9837a62b70bba478ac2179ba8e327185.jpg)
Answer:
measure of the ∠3 is 63°.
Step-by-step explanation:
Given: j is parallel to k and t is the transversal and measure ∠2=117°.
To find: The measure of ∠3
Solution: It is given that the measure of ∠2 is 117° and from the figure, it can be seen that the ∠2 and ∠3 forms a linear pair, thus
⇒∠2 +∠3=180°
⇒117°+∠3=180°
⇒∠3=180-117
⇒∠3=63°
Therefore, the measure of the ∠3 is 63°.