Respuesta :
If the resistance of the wire in the windings of an electric starter motor for an automobile is [tex]2.40\times 10^{-2}\text{ } \Omega[/tex] and the motor is connected to a 13-V battery then the amount of current flow through the motor is [tex]5.42 \times10^2\text{ A}[/tex].
Calculation:
Step-1:
It is given that the resistance of the wire in the windings of an electric starter motor for an automobile is [tex]2.40\times 10^{-2}\text{ } \Omega[/tex] and the motor is connected to a 13-V battery. It is required to find the amount of current flow through the motor.
It is known from Ohm's law, it is known that voltage is the multiplication of the current and the resistance of a circuit.
V=IR
Where V is the voltage, I is current, and R is the resistance.
Step-2:
Substituting the given values into the equation to get the value of the current.
[tex]$\\\begin{aligned}\\V&=IR\\\Rightarrow13 \text{ V}&=I \times 2.40\times10^{-2} \text{ }\Omega\\\Rightarrow I&=\frac{13}{2.40\times10^{-2}} \text{ A}\\ &=5.42 \times10^2\text{ A}\\\end{aligned}\\$[/tex]
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