The lateral and total surface areas of the given cone are 753.98 cm² and 1206.31 cm² respectively.
What are the formulae for lateral and total surface areas of a cone?
A cone has a height 'h', radius 'r', and slant height 'l'.
The slant height of the cone is obtained by the Pythagorean theorem. I.e.,
l² = h² + r²
Then,
Its lateral surface area(LSA) = πr([tex]\sqrt{h^2+r^2}[/tex]) square units and
Its total surface area(TSA) = πr(r + l) square units
Calculation:
It is given that,
A cone has a height h = 16 cm and radius r = 12 cm
Then, the slant height is calculated by
l² = h² + r²
l = [tex]\sqrt{h^2+r^2}[/tex]
On substituting,
l = [tex]\sqrt{16^2+12^2}[/tex]
= [tex]\sqrt{400}[/tex]
= 20 cm
So,
LSA = πr([tex]\sqrt{h^2+r^2}[/tex])
= π × 12 × ([tex]\sqrt{16^2+12^2}[/tex])
= π × 12 × 20
= 753.98 cm²
and
TSA = πr(r + l)
= π × 12 × (12 + 20)
= π × 12 × 32
= 1206.37 cm²
Therefore, the lateral and total surface areas of the cone with a height of 16 cm and a radius of 12 cm are 753.98 cm² and 1206.37 cm².
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