The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
The equation is given as:
y = 3^x
Let x = 0, 1 and 2
y = 3^0 = 1
y = 3^1 = 3
y = 3^2 = 9
So, we have the following ordered pairs (0,1), (1,3) and (2,9)
Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
Read more about exponential functions at:
https://brainly.com/question/2456547
#SPJ1