Water falls without splashing at a rate of 0.400 L/s from a height of 2.20 m into a 0.720-kg bucket on a scale. If the bucket is originally empty, what does the scale read 3.60 s after water starts to accumulate in it

Respuesta :

The reading of the scale after 3.6 seconds is 23.79 N.

Velocity of the water

v = √2gh

v = √(2 x 9.8 x 2.2)

v = 6.57 m/s

Rate of change of momentum of the water after impact

mv/t = F = 0.4 x 6.57 = 2.628 N

Weight of the bucket

Wb = 0.72 x 9.8

Wb = 7.056 N

Weight of the accumulated water

Wa = (RT)g

Wa = (0.4 x 3.6) x 9.8

Wa = 14.11 N

Reading of the scale

R = Wa + Wb + F

R = 14.11 N  +  7.056 N  +  2.628 N

R = 23.79 N

Thus, the reading of the scale after 3.6 seconds is 23.79 N.

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