Question

Suppose the shipping weight of your cheese shop's customized gift baskets is asymmetrically distributed with unknown mean and standard deviation. for a sample of 45 orders, the mean weight is 66 ounces and the standard deviation is 10.2 ounces. what is the upper bound of the 95 percent confidence interval for the gift baskets average shipping weight?
a. note that the correct answer will be evaluated based on the z-values in the summary table in the teaching materials section.
please round your answer to the nearest tenth.
b. note that the correct answer will be evaluated based on the full-precision result you would obtain using excel.

Answer 1

Using the t-distribution, the upper bound of the 95 percent confidence interval for the gift baskets average shipping weight is of 69.06 ounces.

What is a t-distribution confidence interval?

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

• $\overline{x}$ is the sample mean.

• t is the critical value.

• n is the sample size.

• s is the standard deviation for the sample.

For this problem, the parameters are:

$\voerline{x} = 66, t = 2.0154, s = 10.2, n = 45$

Hence the upper bound of the interval is:

$\overline{x} + t\frac{s}{\sqrt{n}} = 66 + 2.0154\frac{10.2}{\sqrt{45}} = 69.06$

More can be learned about the t-distribution at https://brainly.com/question/16162795

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