Question

Objects a and b each have a mass of 25 kilograms. object a has a velocity of 5.98 meters/second. object b is stationary. they undergo a perfectly elastic collision in one dimension. what is the total kinetic energy of the system after the collision?

Answer 1

The total kinetic energy of the system after collision is 223.5J

In elastic collision kinetic energy and momentum are conserved.

According to the question

               mass of object a = 25kg

               mass of object b =  25 kg

        initial velocity of a u1 = 5.98 m/s

        initial velocity  of b u2 = 0

so from momentum conservation-

       mau1 + mbu2 = (m1+m2)v

       25kg × 5.98m/s + 25×0 = (25+25)v

              v = 2.99 m/s

Now the total kinetic energy after the collision will be:

          final kinetic energy = 1/2 (m1+m2) v²

                                           = 1/2 (25+25)× (2.99)²

                                           = 223.5 J

    Thus, total kinetic energy of the system after collision is 223.5J

Learn more about elastic collision here:

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