Question

A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if the mass is doubled to 2m?.

Answer 1

The period is √2 *T if the mass is doubled to 2m.

What is the time period?

The time period is the length of time during which an activity occurs or a condition remains.

The equation for the period T is given as:

$T = 2\pi \sqrt{\frac{m}{k} }$

where k is the spring constant

mass of the system = m

Here,

If the mass id doubled to 2m for the system that is set in motion,

new mass is now  2m

So the equation for time period becomes,

$T' = 2\pi \sqrt{\frac{2m}{k} }$

$T' = \sqrt{2} * 2\pi \sqrt{\frac{m}{k} }$

$T' = \sqrt{2}* T$

Hence,

The period is √2 *T if the mass is doubled to 2m.

Learn more about the time period here:

https://brainly.com/question/17188760

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