The time at which the acceleration is zero is given as 4.66 seconds
First we have to solve for the velocity. To do this, we would have to take the derivative.
[tex]s = e^-0.5t (3 t - 2)[/tex]
Then velocity =
[tex]ds/dt = e^-0.5t (4 - 1.5 t)[/tex]
The acceleration can be gotten by finding the second derivative
[tex]a = dv/dt = e^-0.5t (.75 t - 3.5)[/tex]
To find t at acceleration = 0
We have
[tex]0 = e^-0.5t (.75t - 3.5)[/tex]
This gives t to be
t = 4.66 sec
The displacement of a particle which moves along the s-axis isgiven by
s = (-2+3t)e^(-0.5t), where s is in meters and t is inseconds. Plot the displacement, velocity and acceleration versustime for the first 20 seconds of motion. Determine the time atwhich the acceleration is zero.
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