The electric field due to the nucleus at the location of the electron is 4.101 × 10¹² N/C.
Given:
Distance between the electron and nucleus, r = 26.5 × 10⁻¹² m
Charge on an electron, Q = 1.6 × 10⁻¹⁹ C
Calculation:
We know that the Helium atom (He²⁺) has an atomic number Z = 2 and an atomic mass number A = 2 ( 2 protons + 2 neutrons). Thus the charge of a helium atom can be calculated as:
Q' = +2e = 2(+1.6 × 10⁻¹⁹ C) = 3.2 × 10⁻¹⁹ C
We know that the electric field on charge Q due to the nucleus is given as:
E = kQ' / r²
where E is the electric field
k is Coulomb's force constant
Q' is a charge ona Helium atom
r is the separation distance between the electron and nucleus
Applying values in the above equation we get:
E = (9×10⁹ Nm²/C²) (3.2 × 10⁻¹⁹ C) / (26.5 × 10⁻¹² m)²
= 4.101 × 10¹² N/C
Thus, the electric field on electrons due to the Helium nucleus is of magnitude 4.101 × 10¹² N/C.
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