For a function f(x), the difference quotient is x + one-half h + 15. Which statement explains how to determine the average rate of change of f(x) from x = 5 to x = 8? Substitute 5 for x and 3 for h in the expression x + one-half h + 15. Substitute 5 for x and 8 for h in the expression x + one-half h + 15. Substitute 8 for x and 5 for h in the expression x + one-half h + 15. Substitute 8 for x and 3 for h in the expression x + one-half h + 15.

The average rate of change of f(x) from x = 5 to x = 8 would be gotten by; B: Substituting 5 for x and 8 for h in the expression x + one-half h + 15

How to used difference quotient to find average rate of change?

The difference quotient is defined as a measure of the average rate of change of a function over an interval.

The limit of the difference quotient which is the derivative is the instantaneous rate of change.

This differential quotient in calculus is usually expressed as;

[f(x + h) - f(x)]/h

We are given the differential quotient as;

f(x) = x + ¹/₂h + 15

Thus, the average rate of change of f(x) from x = 5 to x = 8 would be gotten by;

Substituting 5 for x and 8 for h in the expression x + one-half h + 15

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