Question

Solve 3[-x + (2 x +1)]=x-1

Answer 1

Question :

• Solve 3 [-x + (2x + 1) ] = x - 1

Solution :

⇒ 3 [-x + 2x + 1] = x - 1

⇒ 3 [x + 1] = x - 1

⇒ 3 × [x + 1] = x - 1

⇒ 3x + 3 = x - 1

⇒ 3x - x + 3 = -1

⇒ 2x + 3 = -1

⇒ 2x = -1 - 3

⇒ 2x = -4

⇒ x = -4 / 2

⇒ x = -2

Answer 2

Simplifying

3[-1x + (2x + 1)] = x + -1

Reorder the terms:

• 3[-1x + (1 + 2x)] = x + -1

Remove parentheses around (1 + 2x)

• 3[-1x + 1 + 2x] = x + -1

Reorder the terms:

• 3[1 + -1x + 2x] = x + -1

Combine like terms: -1x + 2x = 1x

• 3[1 + 1x] = x + -1

• [1 * 3 + 1x * 3] = x + -1

• [3 + 3x] = x + -1

Reorder the terms:

• 3 + 3x = -1 + x

Solving

• 3 + 3x = -1 + x

Solving for the variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.

• 3 + 3x + -1x = -1 + x + -1x

Combine like terms: 3x + -1x = 2x

• 3 + 2x = -1 + x + -1x

Combine like terms: x + -1x = 0

• 3 + 2x = -1 + 0
• 3 + 2x = -1

Add '-3' to each side of the equation.

3 + -3 + 2x = -1 + -3

Combine like terms: 3 + -3 = 0

• 0 + 2x = -1 + -3
• 2x = -1 + -3

Combine like terms: -1 + -3 = -4

• 2x = -4

Divide each side by '2'.

• x = -2

Simplifying

• x = -2