Question

A body and tackle with a velocity ratio of 5 is used to raise a mass of 50kg through a vertical distance of 20n at a steady rate if the effort is equal to 80n. Determine (a) distance moved by effort (b)the workdone by the effort in lifting the load (c)the losses in energy involve the operating in machine​

Answer 1

A. The distance moved by the effort is 100 m

B. The workdone by the effort in lifting the load is 8000 J

C. The losses in energy involve the operating in machine 1800 J

A. How to determine the distance moved by the effort

• Velocity ratio = 5
• Load distance = 20 m
• Effort distance =?

Velocity ratio = Effort distance / Load distance

5 = Effort distance / 20

Cross multiply

Effort distance = 5 × 20

Effort distance = 100 m

B. How to determine the work done by the effort

• Effort distance = 100
• Effort = 80 N
• Workdone by effort =?

Workdone = force × distance

Workdone by effort = 80 × 100

Workdone by effort = 8000 J

C. How to determine the losses in the energy

We'll begin by calculating the workdone in lifting the load. This is illustrated below:

• Mass (m) = 50 Kg
• Acceleration due to gravity (g) = 9.8 m/s²
• Height (h) = 20 m
• Workdone =?

Workdone = mgh

Workdone = 50 × 9.8 × 20

Workdone = 9800 J

Now, we can determine the energy lost as follow:

• Workdone = 9800 J
• Workdone by effort = 8000 J
• Energy lost =?

Energy lost = 9800 - 8000

Energy lost = 1800 J

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