If f(x) = –x2 + 3x + 5 and g(x) = x2 + 2x, which graph shows the graph of (f + g)(x)? On a coordinate plane, a straight line with a negative slope crosses the y-axis at (0, 5) and crosses the x-axis at (1, 0). On a coordinate plane, a parabola opens down. It goes through (negative 2, negative 4), has a vertex at (0, 5), and goes through (2, negative 2) On a coordinate plane, a parabola opens up. It goes through (negative 3, 7), has a vertex at (negative 1, 2), and goes through (0, 5). On a coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5) - edge21

The graph of (f+g)(x) is on the coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5).

What is the graph of a parabolic equation?

The graph of a parabolic equation is a curved U-shape graph from where the domain, the range, x-intercept(s), and the y-intercept(s) can be determined.

Given that:

f(x) = -x² + 3x + 5

g(x) = x² + 2x

To find (f + g)(x), we have:

(f + g)(x) = (-x² + 3x + 5)+(x² + 2x)

(f + g)(x) = -x² + 3x + 5 +x² + 2x

(f + g)(x) = 3x + 2x + 5

(f + g)(x) = 5x + 5

Use the Slope-intercept form: We are to find the graph of y = 5x + 5

y = 5x + 5

Here:

Slope = 5
x-intercept = (-1, 0)
y-intercept = (0,5)

Therefore, we can conclude that on the coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5)

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