Question

Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

The equations that can be used are y * (y - 5) = 750, y^2 - 5y = 750 and (y + 25)(y – 30) = 0

How to determine the equations?

The given parameters are:

Length = y

Width = y - 5

Area = 750

The area of a rectangle is:

Area = Length * Width

So, we have:

y * (y - 5) = 750

Expand

y^2 - 5y = 750

Rewrite as:

y^2 - 5y - 750 = 0

Factorize

(y + 25)(y – 30) = 0

Hence, the equations that can be used are y * (y - 5) = 750, y^2 - 5y = 750 and (y + 25)(y – 30) = 0

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Complete question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room?