find the area of following figure...?
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Answer:
33600 m²
Step-by-step explanation:
The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.
area of trapezoid = (a + b)h/2
where a and b are the lengths of the bases, and h is the height.
We need to find the height, BC.
Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.
DE + EC = DC
EC = AB = 360 m
DC = 600 m
DE + 360 m = 600 m
DE = 240 m
Use right triangle ADE to find AE. Then BC = AE.
DE² + AE² = AD²
DE² + 240² = 250²
DE² = 62500 - 57600
DE² = 4900
DE = √4900
DE = 70
BC = 70 = h
area = (a + b)h/2
area = (600 m + 360 m)(70 m)/2
area = 33600 m²
Answer:
33,600 m^2.
Step-by-step explanation:
This is a trapezium, so
Area = (h/2)(a + b)
= (h/2) ( 360 + 600)
= 960h / 2
= 480h,
We find the value of h using Pythagoras:
250^2 = h^2 + (600-360)^2
h^2 = 250^2 - 240^2 = 4900
h = 70.
So the Area = 70 * 480
= 33,600 m^2