i. P(A) = 0. 4
ii. P(AB) = 0. 9
iii. P(A∩B) =0. 25
From the information given,
Universal set = 40% + 50% + 25% = 0.40 + 0. 50 + 0. 25
A = Mechanical defects = 40%
B = Electrical defects = 50%
A∩B =25%
i. Probability of A , P(A)
= [tex]\frac{40}{100}[/tex]
= [tex]0. 4[/tex]
ii. Probability of B, P(AB)
= [tex]\frac{40}{100} + \frac{50}{100}[/tex]
= [tex]0. 4 + 0. 5[/tex]
= [tex]0. 9[/tex]
iii. Probability of A∩B entails the common factor between A and B
P(A∩B) = [tex]\frac{25}{100}[/tex] = [tex]0. 25[/tex]
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