The X and Y components are as follows;
1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s
2. X = 12 * -cos 34 = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s
3. X = 8 * -cos 90 = 0 m/s; Y = 12 -sin 90 = -8 m/s
4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) = -19.3 m/s
What are the horizontal and vertical components of the vectors?
The horizontal and vertical components of the velocities are given as follows:
- Horizontal component, X = x cos θ
- Vertical component, Y = y sin θ
1. 35 m/s at 57° from x-axis
X = 35 * cos 57 = 19. 1m/s
Y = 35 * sin 57 = 29.4 m/s
2. 12m/s at 34° S of W
X = 12 * -cos 34 = -10 m/s
Y = 12 * -sin 34 = -6.7 m/s
3. 8 m/s at South
X = 8 * -cos 90 = 0 m/s
Y = 12 -sin 90 = -8 m/s
4. 20 m/s at 275° from x-axis
X = 20 * cos 75 = 5. 2m/s
Y = 20 * (-sin 75) = -19.3 m/s
In conclusion, the X and Y components are found by taking cosines and sine of the angles.
Learn more about horizontal and vertical components at: https://brainly.com/question/26446720
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