Question

PLS HELP I REALLY NEED HELP

Answer 1

Answer:

• a) AB = 10 units
• b) Midpoint is (2, 6)

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Given

• Points A( - 1, 10) and B(5, 2)

To find

• a) The length of AB
• b) The midpoint of AB

Solution

a) Use the distance formula:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates and calculate:

$d=\sqrt{(5-(-1))^2+(2-10)^2} =\sqrt{6^2+(-8)^2} =\sqrt{36+64} =\sqrt{100} =10$

The distance is AB = 10 units

b) Use midpoint formula and find x and y- coordinates of this point:

$x= \cfrac{x_1+x_2}{2}$    and    $y= \cfrac{y_1+y_2}{2}$

Substitute coordinates and find the midpoint:

$x= \cfrac{-1+5}{2} =2$  and  $y= \cfrac{10+2}{2}=6$

The midpoint is (2, 6)

Answer 2

Answer:

Length of line segment AB = 10 units

Midpoint of line segment AB = (2, 6)

Step-by-step explanation:

To find length, apply the distance formula :

• AB = √(5 - (-1))² + (2 - 10)²
• AB = √36 + 64 = √100
• $\fbox {AB = 10 units}$

To find the midpoint :

• M = (-1 + 5 / 2, 10 + 2 / 2)
• $\fbox {Midpoint = (2, 6)}$