The 3kg object in Figure is released from rest at a height of on a curved frictionless ramp.
At the foot of the ramp is a spring of force constant 400N/m. The object slides down the
ramp and into the spring, compressing it a distance before coming momentarily to rest.
a) Find
b) Describe the motion of the object (if any) after
the block momentarily comes to rest?

The object is falling from the rest and it is assumed that the friction on the ramp is zero and the air resistance is also considered to be zero so only the gravitational force acts and the total potential energy gets converted to Kinetic Energy.

The total amount of potential energy at the top of the ramp is given by

Ep=mgh

Ep=3 * 9.81 *5

Ep=147.15 Joules

This is equal to kinetic energy.

From the formula for elastic potential energy

The distance up to which the spring is compressed is determined

The force constant = 400N/m

147.15 =(1/2)k(x²)

294.3=(400)(x²)

0.73575=x²

x=0.8577 m

So, the object compresses the spring up to 0.8577m.

When the object compresses the spring, the potential energy of the spring is converted into Kinetic Energy so it will push the object back again.

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