Question

In the air, it had an average speed of 16 \text{m/s}m/start text, m, slash, s, end text. In the water, it had an average speed of 33 \text{m/s}m/start text, m, slash, s, end text before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds.
How long did the stone fall in the air and how long did it fall in the water?

Answer 1

The time taken by the stone to fall in air is 7 seconds and the time taken in water is 5 seconds.

What is Speed?

Speed is the distance covered by an object in a fixed period of time. It is measured in m/sec.

The average speed in air is 16m/sec.

The average speed in water is 33m/sec.

The total time taken is 12 seconds.

Total distance covered =  Total time taken * speed at which it covered the distance

Let the time taken to fall in air is t

So, the time taken in water will be 12-t

The total distance is equal to

127 = 16*t + 3(12-t)

127 = 16t + 36 - 3t

127 - 36 = 16t - 3t

91 = 13t

t = 91/13 = 7 seconds

12-t = 12-7 =5 seconds

Therefore, the time taken by the stone to fall in air is 7 seconds and the time taken in water is 5 seconds.

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