Question

How many moles of oxygen atoms are contained in 9.9 moles of KClO3 (potassium chlorate)?

Answer 1

Answer:

Explanation:

Comment

1 mole of KClO3 has 3 moles of oxygen

9.9 moles of KClO3 has x moles of oxygen

Formula

1/9.9 = 3/x                                    Cross Multiply

Solution

1 / 9.9 = 3 / x

1*x = 9.9 * 3

x = 29.7 moles of oxygen

1 mole of oxygen has 6.02 * 10^23 atoms making up that 1 mole

29.7 moles of oxygen has 6.02*10^23 atoms making them up.

Answer

29.7 * 6.02 * 10^23 atoms

1.78 * 10^25 atoms

Answer 2

Calculate atoms in KClO_3

• K=1
• Cl=1
• O=3

1 mol KCl contains 3mol O_2

9.9 mol contains

• 9.9(3)
• 29.7mol O_2