Question

If the coefficient of kinetic friction between a 24-kg crate and the floor is 0.25 what horizontal force is required to move the crate at a steady speed across the floor?

Answer 1

The horizontal force required to move the crate at a steady speed across the floor will be 58.86 N.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

The given data in the problem is;

Mass,m = 24 kg

The coefficient of kinetic friction, μ=0.25

The friction force is defined as the product of the coefficient of friction and normal reaction.

f=μN

If there is no other force, the horizontal force is equal to the friction force;

F=f

The horizontal force required to move the crate at a steady speed across the floor is found as;

F = μN

The normal reaction force is;

N=W

N=mg

F = μmg

F=0.25 ×  24-kg × 9.81 m/s²

F = 58.86 N

Hence horizontal force is required to move the crate at a steady speed across the floor will be 58.86 N.

To learn more about the friction force, refer to the link;

https://brainly.com/question/1714663

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