Question

A gas is contained in a thick-walled
balloon. When the pressure
changes from 1.21 atm to 2.52 atm,
the volume changes from 3.75 L to
1.72 L and the temperature changes
from 293 K to____________ K.
Which variable is held constant?
A.P B.V C.n D.T
Thank you! :)

Answer 1

Answer:

C.) n

Explanation:

-----> P = pressure (atm)

-----> V = volume (L)

-----> T = temperature (K)

-----> n = number of moles

According to the problem, it seems like pressure (P), volume (V), and temperature (T) are all changing. The problem never brings up whether the number of moles (n) has changed. Therefore, the number of moles (n) must have been held constant.

________________________________________________________

If you need to know what the temperature changes to....

When the number of moles is held constant, you can find the change in the other variables using the Combined Gas Law equation:

P₁V₁ / T₁ = P₂V₂ / T₂

In this formula, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature. You can find the final temperature by plugging in the given values and simplifying.

P₁ = 1.21 atm                      P₂ = 2.52 atm

V₁ = 3.75 L                        V₂ = 1.72 L

T₁ = 293 K                         T₂ = ? K

P₁V₁ / T₁ = P₂V₂ / T₂                                       <----- Equation

(1.21 atm)(3.75 L) / (293 K) = (2.52 atm)(1.72 L) / T₂         <----- Insert values

0.015486 =  (2.52 atm)(1.72 L) / T₂              <----- Simplify left side

0.015486 = 4.3344 / T₂                               <----- Multiply 2.52 and 1.72

0.015486 x T₂ = 4.3344                               <----- Multiply both sides by T₂

T₂ = 279.885                                                <----- Divide both sides by 0.015486

T₂ = 280 K                                                   <----- Answer in correct sig figs